Question

What is the % of h2O in Fe(CNS)3.3H2O

Answer 1

this blog help u!!
total molecular weight= 236.

weight of 3h2o = 54

by in typing usually like :-

54 / 236 ×100= 22.881%

i hope help u

Answer 2

Answer : The % of $H_2O$ in $Fe(CNS)_3.3H_2O$ is, 19 %

Explanation :

First we have to calculate the molar mass of $Fe(CNS)_3.3H_2O$ and $H_2O$.

The molar mass of $H_2O$ = 18 g/mole

The molar mass of $Fe(CNS)_3.3H_2O$ = $56+3(12+14+32)+3(18)=284g/mole$

Now we have to calculate the % of $H_2O$ in $Fe(CNS)_3.3H_2O$.

From the given formula, we conclude that 1 mole of $Fe(CNS)_3.3H_2O$ contains 3 mole of $H_2O$.

$\%\text{ of }H_2O=\frac{\text{Mass of }H_2O}{\text{Mass of }Fe(CNS)_3.3H_2O}\times 100$

Now put all the given values in this expression, we get :

$\%\text{ of }H_2O=\frac{3\times 18g/mole}{284g/mole}\times 100=19\%$

Therefore, the % of $H_2O$ in $Fe(CNS)_3.3H_2O$ is, 19 %