What is the [oh-] in a sample of lime juice with a ph of 2.0?
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Given: pH=2.3pH=2.3
pH is defined as the logarithm of the reciprocal of the hydrogen ion concentration:
pH=−log[H+]pH=−log[H+]
Replace pHpH by 2.32.3:
2.3=−log[H+]2.3=−log[H+]
Multiply each side of the inequality by −1−1:
−2.0=log[H+]−2.0=log[H+]
Take the exponential with base 10 of each side:
10−2.0=10log[H+]=[H+]10−2.0=10log[H+]=[H+]
Interchange the left and right side and evaluate:
[H+]=10*-2.0
pH is defined as the logarithm of the reciprocal of the hydrogen ion concentration:
pH=−log[H+]pH=−log[H+]
Replace pHpH by 2.32.3:
2.3=−log[H+]2.3=−log[H+]
Multiply each side of the inequality by −1−1:
−2.0=log[H+]−2.0=log[H+]
Take the exponential with base 10 of each side:
10−2.0=10log[H+]=[H+]10−2.0=10log[H+]=[H+]
Interchange the left and right side and evaluate:
[H+]=10*-2.0
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