Question

WHAT IS THE [OH-] IN THE FINAL SOLUTION PREPARED BY MIXING 20.0 ML OF 0.050 M HCL WITH 30.0 ML OF 0.10 M Ba(OH)2 ?

0.12 M

0.10 M

0.40 M

0.0050 M

HOW TO SOLVE EASILY ....?

Answer 1

Answer:

H+ ions present in HCl solution:  20.0/1000 * 0.050 = 0.001 moles

There are two OH- ions in a molecule of Ba (OH)2.

OH- ions released in the Barium Hydroxide solution =

        = 2 * 30.0/1000 * 0.10 = 0.006 moles

So 0.001 moles of H+ and OH- combine to form water.

So 0.005 moles of OH- remain. So the molarity of [ OH- ]

            = 0.005 moles / (20+30) ml   =0.100 M

PLZZ MARK ME AS BRAINLIST ✌✌