Question

what is the order of decomposition of ammonia on the surface of platinum catalyst

Answer 1

The answer is "Zero order Reaction" .

The decomposition of ammonia on a surface of ammonium catalyst is zero order reaction.

Reason/Explanation :-

NH₃(g) ----- N₂(g) + 3H₂(g)

Here reaction rate = K[NH₃]⁰

Hence it signifies that here platinum metal will be acting like as catalyst.

Note - In the catalyst conversion, where rate of reaction do not depend on the concentration of ammonia , hence the reaction will be zero order reaction.

Since we know that at very high pressure the platinum gets saturated with the molecule of ammonia, so no space is left there even after increasing the concentration ammonia.

Hope it helps.

Answer 2

Answer:

Decomposition of ammonia on the surface of platinum catalyst is zero order.

Explanation:

The decomposition reaction of ammonia in the presence of platinum is as follows:

               $2 N H_{3} \stackrel{p t}{\rightarrow} N_{2}+3 H_{2}$

From the above decomposition reaction , one mole of ammonia decomposed into one mole of nitrogen and three moles of hydrogen.

               $Rate =\mathrm{k}\left[\mathrm{NH}_{3}\right]^{0}.$

• Platinum metal acts as catalyst.
• Since the platinum becomes saturated with ammonia molecule at elevated pressure.
• If the ammonia concentration is also increased, there is no more space available. So the reaction follows zero order.