what is the output of following c program
#include
int main() {
int x=1;
printf("%d %d %d", x, x++, ++x);
return 0;
}
and reason in detail
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Answer:
1 2 2
Explanation:
x=1
X++ = x+1 = 1+1 = 2
++X = 1+x = 1+1 = 2
fazeelkhalid9:
are you programmer
if yes then read my code again again again again...........
can you tell me what is the purpose of x++ and ++x
Not really a programmer
I have studied C
when you put increment operator after any variable(s), increment is done later and if you put before variable(s) increment is done first.
Eg. if x = 3 and y is 2 then x-y++ is equal to 2
++x-y is equal to 2
However 1 gets added to x-y in first case and 1 gets added to x in the second case.
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