Question

what is the output of the following C code ??
#include <studio.h>
int main()
{
int X= 1;
if (X= =0)
if (X> =0)
printed("false\n");
else
Printf ("false\n")
return 0;
}

a) true
b) false
c) depands on computer
d) No print statement​

Answer 1

Answer:

No print statement

@user died

Answer 2

#include <stdio.h>

int main()

{

float f = 0.1;

if (f == 0.1)

printf("True");

else

printf("False");

return 0;

}

The output is false.

#include <stdio.h>

int main()

{

float f = 0.1;

if (f == (float)0.1)

printf("True");

else

printf("False");

return 0;

}

Now shows the correct output. Whats the reason behind this?

Also what is the reason of this behavior.

#include <stdio.h>

main()

{

int n = 0, m = 0;

if (n > 0)

if (m > 0)

printf("True");

else

printf("False");

}