Question

What is the output of the following code?
class class1:
a = 1
def f1(self):
a = 2
class1.a += 1
print(class1.a, end=' ')
print(a, end=' ')
class1().f1()
class1().f1()


2 3 3 2

2 2 2 2

2 2 3 2

2 2 3 3

Answer 1

Python Program

Answer for the code is:

2 2 3 2

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Answer 2

The output of the code

class class1:

       a = 1

def f1(self):

       a = 2

       class1.a += 1

       print(class1.a, end=' ')

       print(a, end=' ')

class1().f1()

class1().f1()

is :

2 2 3 2

• When the first method class1().f1() was called then initially 2 was printed because "class1.a =1"  and according to the code

        class1.a += 1 ,

        which gives class1.a = 2

• After that again 2 is printed as "a = 2" in the f1 block.

• When the second method class1().f1() was called then class1.a =3 because class1.a becomes 2 after the first method was called.

• After that 2 is printed because still a is equal 2 in the f1 block.