Question

What is the output of the following snippet?
s=0
for s in range(5):
print(s)

Answer 1

Given Code :

s=0

for s in range(5):

print(s)

Output :

Indentation Error raises.

Reason :

A loop must consist alteast one statement in it. else, the interpreter considers it as an Indent error thinking that the next statements should be in the loop.

Let us check what happens if we make a slight change in the code.

s=0

for s in range(5):

   print(s)

Output :

0

1

2

3

4

Explanation :

• Here, we initialized s with 0. On entering the loop, where the range is mentioned as 5.

• s in range(5) means range(5) creates a iterable from 0 to 5 excluding 5 as (0, 1, 2, 3, 4) with increment of 1 on every iteration

• So, on first iteration s is filled with the first element of the iterable which is 0. As now s=0, print(s) prints 0.

• Then the next value 1 will be stored in s, by incrementation over iteration and then goes into the loop, prints 1.

• Similarly, the loop runs and prints 2, 3, 4 too.

• Now, the printed numbers are 0, 1, 2, 3, 4. That means 5 iterations are happened already.

• On 6th iteration, the value becomes 5 on incremention, which is excluded. As the condition fails, the loop terminates leaving the final output as 0, 1, 2, 3, 4 each printed on a new line.

Learn more :

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2. Write a simple python function to increase the value of any number by a constant "C=5"

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