what is the oxidation no. of H2S2O7
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18
2+2x+7(-2)=0 find X X is the oxidation number
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Answered by
11
+6.................let ox. state of s in h2so4 be x.
then +2+2x+( -2)×7 = o
2x = 14-2
x = 12/2 = 6
then +2+2x+( -2)×7 = o
2x = 14-2
x = 12/2 = 6
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