what is the oxidation no. of s in S2O82-
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In S2O8, there is one peroxy linkage. Hence two of the eight oxygen atoms have -1 oxidation state.
Hence,
2x + 6(-2)+2(-1)=-2
2x = 14-2= 12
x =+6
Hence,
2x + 6(-2)+2(-1)=-2
2x = 14-2= 12
x =+6
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