What is the Oxidation number of of Sulphur in H2S2O8
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Each one is having +6 oxidation State.
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Hi!!!
Let the oxidation no. of s be x
2 ( +1 ) + 2x + 8 ( - 2 ) = 0
2x = 14
x = +7
Therefore oxidation no. of s is +7
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Let the oxidation no. of s be x
2 ( +1 ) + 2x + 8 ( - 2 ) = 0
2x = 14
x = +7
Therefore oxidation no. of s is +7
Have a nice time
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