What is the oxidation number of phosphorus in H₃PO₂ molecule?
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Answered by
2
Letting y be the oxidation number of phosphoris 3 + x + 2(-2) = 0 => x =1 1oxidation number of P= +1
Answered by
2
Let oxidation state of p is x
The.3(1)+x+2(-2) =0
3+x-4=0
X-1=0
X=1
Hence oxidation state of p is 1
The.3(1)+x+2(-2) =0
3+x-4=0
X-1=0
X=1
Hence oxidation state of p is 1
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