Question

What is the Oxidation Number Of Sulphur In H2S2O8

Answer 1

Answer:

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Answer 2

$\color{darkblue}\underline{\underline{\sf Oxidation\: Number-}}$

It represents the number of Electron gained or lost by atom when it changes in Compound from a free state.

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It is the charge developed on an atom when is in combination.

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Oxidation number of ${\sf H_2S_2O_8}$

We know that -

Oxidation number of H = 1

Oxidation number of O = -2

Let , x be the oxidation number of S

Therefore ,

$\implies{\sf (1×2)+2x+(8×-2)=0}$

$\implies{\sf 2+2x-16=0 }$

$\implies{\sf 2x=14 }$

$\implies{\sf x=\dfrac{14}{2}}$

$\color{red}\implies{\sf x=+7}$

$\color{darkblue}\underline{\underline{\sf Answer-}}$

Oxidation number of sulphur is $\color{red}{\sf +7}$