Question

What is the oxidation number of Zn(OH) 4^2-?

Answer 1

Oxidation no. Of

Zn2+ = +2

OH- = -1
Oxidation number of OH- is -1.
X is oxd no. of zinc.
x + 4(-1) = -2

x - 4 = -2

x = -2 +4

x = +2
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Answer 2

The oxidation number of $Zn(OH)_4^{2-}$is -2

Explanation:

• To find the oxidation number of complete substance or ions, the oxidation number of each element in the substance must be identified.
• In $Zn(OH)_4^{2-}$, the oxidation number of each component is as follows

1. Zn = +2
2. O = -2
3. H = +1

• As there are four oxygen present, the oxidation number of oxygen is -2 × 4 which is -8.
• As there are four hydrogen present, the oxidation number of hydrogen is 1 × 4 which is 4.
• Thus the oxidation number of $Zn(OH)_4^{2-}$ is

$Zn(OH)_4^{2-}$ = (+2) + (-8) + (4)

$Zn(OH)_4^{2-}$ = (+6) + (-8)

$Zn(OH)_4^{2-}$= -2

∴ The oxidation number of $Zn(OH)_4^{2-}$is identified as -2.

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