what is the oxidation of Cr in Cr2(So4)3
Answers
Answered by
99
Cr2(SO4)3
2x+3 (-2)=0
2x=6
X=+3
Oxidation state of cr is +3
2x+3 (-2)=0
2x=6
X=+3
Oxidation state of cr is +3
Answered by
140
Hello friend !!!
Here's the answer you are looking for
Let us consider the oxidation number of Cr is x
Since Cr2(SO4)3 is a molecule, it's oxidation number is 0.
And the oxidation number of (SO4) is always -2.
So, mathematically,
2x + 3(-2) = 0
2x = +6
x = +3
Therefore, the oxidation number of Cr in Cr2(SO4)3 is +3.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Let us consider the oxidation number of Cr is x
Since Cr2(SO4)3 is a molecule, it's oxidation number is 0.
And the oxidation number of (SO4) is always -2.
So, mathematically,
2x + 3(-2) = 0
2x = +6
x = +3
Therefore, the oxidation number of Cr in Cr2(SO4)3 is +3.
★★ HOPE THAT HELPS ☺️ ★★
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