Question

What is the oxidation state and covalency of [Al Br(NH3)5]2+

Answer 1

Answer:

Explanation:

Oxidation state ofAl=+3

Covalency= 6

Answer 2

Given:

The given complex is $[AlBr(NH_3)_5]^{+2}$.

To find:

The oxidation state and covalency.

Solution:

The complex is $[AlBr(NH_3)_5]^{+2}$.

Let the oxidation state of Al is x.

The charge on ammonia is 0 and the charge on Br is -1.

The overall charge of the complex is +2.

So, we can write-

$x - 1 = + 2 \\ x = + 3$

The value of x is +3.

The oxidation state of Al is +3.

Now Al is attached with six ligands so, its covalency is 6.

The oxidation state of Al is +3 and its covalency is 6.