what is the oxidation state of sb in hsbf6
Answers
Answered by
0
Answer:
don't know
Explanation:
because i have not studed
Answered by
1
Explanation:
The oxidation no. of Sb in HSbF6 is:-
H = +1 Sb = x F = -1 (-6)
+1+X+(-6) =0
1-6=0
-5=0
= +5
The oxidation no. Of Sb in HSbF6 is +5
Similar questions