what is the percent by mass of water in Epsom salt, MgSO4*7H2O?
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Answer:
Relative molecular mass of MgSO4.7H2O
= 24+32+16×4+7×(2+16)
= 24 +32+64+126
=246
246g of Epsom salt contains 126g of water
∴ 100g will contain 126×100246
= 12600246
= 51.21gofH2O
∴ The %ofH2OinMgSO4.7H2O = 51. 21
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