What is the percent (%m/v) of a solution prepared by diluting 10.0 ml of 9.00% naoh to 60.0 ml?
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Answer:
1.5%
Explanation:
9% solution= 9÷40×1000÷100= 2.25 molar
now M1V1=M2V2
2.25X10=M2X60
M2=2.25×10÷60= 0.375 m
% 0.375x40/1000 ×100= 1.5 %
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