Question

What is the percentage composition of water in cuso4 5h2o?

Answer 1

Cu = 63.55 g/mol

S = 32.07 g/mol

O x 4 = 16.00 g/mol x 4 = 64.00 g/mol

H2O x 5 = 18.02 g/mol x 5 = 90.10 g/mol

After adding them all up you get 249.72g/mol

90.10 grams is water, so to find the percentage by mass that is water, simply divide 90.10 g by 249.72 g and multiply the result by 100%:

90.10/249.72*100%=36.08%