Question

What is the percentage of carbon in acetic acid? (at mass of C = 12 u, H = 1 u, O = 16 u) ?

Answer 1

Answer:

carbon=24

molecule mass=60

carbon%=24/60*100=40%

Answer 2

Answer:

C - 12

H - 1

O - 16

CH3COOH

12+3+12+32+1

Total mass - 60

mass of C..

total amt. of C = 24

24/60× 100

=40.0%