Question

what is the percentage of major product of mono chlorination of isopentane.
pls soon.

Answer 1

Answer:

In terms per hydrogen atom, the experimental yield is

22 % / 1 = 22 % → 2-chloro-2-methylbutane

33 % / 2 = 16.5 % → 2-chloro-3-methylbutane

30 % / 6 = 5 % → 1-chloro-2-methylbutane

15 % / 3 = 5 % → 1-chloro-3-methylbutane

Explanation:

Thus, 2-chloro-2-methylbutane is indeed slightly preferred – as you have expected.