what is the percentage of oxygen in Ca(NO3)2
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the molecular mass of the given compound=
40+(14+16×3)2=164 grams or u.
then the percentage of O=96/164×100=58.53%≈58.5%.
40+(14+16×3)2=164 grams or u.
then the percentage of O=96/164×100=58.53%≈58.5%.
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