Question

What is the perimeter of a rectangle whose adjacent sides are (3a – b) and (–a + 6b)?

A
2a + 5b

B
4a + 10b

C
4a – 7b

D
2a – 5b

Answer 1

Answer:

c one is the correct answer

Answer 2

Step-by-step explanation:

adjacent sides of rectangle are l=(3a – b) and b= (–a + 6b)

perimeter=2(l+b)

2[3a-b+(-a+6b)]

=2(3a-a-b+6b]

=2(2a+5b)

=4a+10b

Perimeter of rectangle is (4a+10b)

Option B