what is the perimeter of a rectangle whose area is 52 cm and length 88.2 mm
Answers
Answered by
0
l≈0.088m
A=wl
P=2(l+w)
Solving forP
P= 2 l + 2 A/l=2·88.2+2·52/0.088
≈176.40012m
P≈1.18×106mm
I hope its help you
mark brainliest
A=wl
P=2(l+w)
Solving forP
P= 2 l + 2 A/l=2·88.2+2·52/0.088
≈176.40012m
P≈1.18×106mm
I hope its help you
mark brainliest
Answered by
0
Length = 88.2mm = 8.82 cm
Area of rectangle = l×b
52cm sq. = 8.82×b
b = 5.89cm
Perimeter of rectangle = 2 (l+b)
= 2 (8.82+5.89)
= 29.42cm
Hope it is helpful.
Area of rectangle = l×b
52cm sq. = 8.82×b
b = 5.89cm
Perimeter of rectangle = 2 (l+b)
= 2 (8.82+5.89)
= 29.42cm
Hope it is helpful.
9005012040:
Please mark it as brainliest if u got help from my answer.
Similar questions