Question

What is the perimeter of a sector of a circle whose central angle is 90 degree and radius is 7 cm

Answer 1

perimeter of a sector m90°=(1/2)πr+2r
=((1/2)×(22/7)×7)+(2×7)
=11+14
=25cm
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Answer 2

The perimeter of a sector of a circle is 25 cm

Solution:

The perimeter of sector of circle is given as:

$Perimeter\ of\ sector = \frac{ \theta }{360} \times 2 \pi r + 2r$

Where,

r is the radius

$\theta$ is the central angle in degrees

Given that,

Central angle = 90 degrees

Radius = 7 cm

Substituting we get,

$Perimeter\ of\ sector = \frac{ 90 }{360} \times 2 \times 3.14 \times 7 + 2(7)\\\\Perimeter\ of\ sector = 10.99 + 14\\\\Perimeter\ of\ sector = 24.99 \approx 25$

Thus, perimeter of a sector of a circle is 25 cm

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