Question

what is the perimeter of the base of a cylinder​

Answer 1

Answer:

Height=10 cm

Circumference of base=15.4 cm

\begin{gathered}2\pi r = \frac{154}{10} \\ 2 \times \frac{22}{7} \times r = \frac{154}{10} \\ r = \frac{154 \times 7}{10 \times 2 \times 22} \\ \\ r = \frac{1078}{440} = 2.45\end{gathered}

2πr=

10

154

2×

7

22

×r=

10

154

r=

10×2×22

154×7

r=

440

1078

=2.45

Radius of cylinder=2.45 cm

\begin{gathered}volume \: of \: cylinder \\ \pi r {}^{2} h = \frac{22}{7} \times 2.45 \times 2.45 \times 10 \\ = \frac{22}{7} \times \frac{245}{100} \times \frac{245}{100} \times 10 \\ = \frac{13205500}{70000} \\ = 188.65\end{gathered}

volumeofcylinder

πr

2

h=

7

22

×2.45×2.45×10

=

7

22

×

100

245

×

100

245

×10

=

70000

13205500

=188.65

So, volume of cylinder is 188.65cm^3.

Answer 2

2pie r

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