Question

. What is the perpendicular distance between the force and the turning point if a force of 25 N produces a moment of force 250 Nm?​

Answer 1

Answer:

F  = 525N

τ = 420N  - m

Moment of force

= Force × Perpendicular distance

∴420N − m=  525N × Perpendicular distance.

∴ Perpendicular distance

=  420/525 = 0.8m

0.8 m is the shortest distance between the point of application of force and the turning point.

Answer 2

Answer:

Moment of force =F*d

250NM=25N*D

250NM/25N=D

100=D

Ans =100