. What is the perpendicular distance between the force and the turning point if a force of 25 N produces a moment of force 250 Nm?
Answers
Answered by
1
Answer:
F = 525N
τ = 420N - m
Moment of force
= Force × Perpendicular distance
∴420N − m= 525N × Perpendicular distance.
∴ Perpendicular distance
= 420/525 = 0.8m
0.8 m is the shortest distance between the point of application of force and the turning point.
Answered by
0
Answer:
Moment of force =F*d
250NM=25N*D
250NM/25N=D
100=D
Ans =100
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