what is the pH of 0.05 of Ba(OH)2
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Answered by
2
its 13 if u want explanation plzz see below
Ba(OH)2 ↔ Ba2+ + 2OH-
0.05M Ba(OH)2 = 0.05*2 = 0.1MOH-
[OH-] = 0.1
pOH= -log 0.1
pOH = 1.00
pH = 14.00-pOH
pH = 13.00
Ba(OH)2 ↔ Ba2+ + 2OH-
0.05M Ba(OH)2 = 0.05*2 = 0.1MOH-
[OH-] = 0.1
pOH= -log 0.1
pOH = 1.00
pH = 14.00-pOH
pH = 13.00
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wher 14 comes from
Answered by
2
Its ph will be 13.
as: Ba(OH)2 - Ba2+ + 2OH- 0.05 M X 2= 0.10M pOH= -log(0.10 M) = 1.00
pH = 14-pOH
= 14 - 1.00=13
wher 14 comes from
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