Question

What is the pH of 0.05M Ba(OH)2​

Answer 1

Answer:

use the answer attached

Answer 2

Explanation:

Ba(OH) 2⟶Ba +2 +2OH −

∴[OH − ]=0.05×2=0.10M

⇒pOH=−log(0.10)=1

As we know that,

pH+pOH=14

∴pH=14−pOH=14−1=13

Hope it helps

PLZ MARK AS BRAINLIEST