Chemistry, asked by cindyvillegas, 11 months ago

What is the pH of a 0.235 M Ba(OH)2 solution?

Answers

Answered by fardeenferozkhan

2

Answer:

pOH = -log [OH-]

= - log [ 0.235]

pOH = 0.62

pH = 14 - pOH

= 14 - 0.62

pH = 13.37

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