What is the pH of a 0.309 M solution of hypobromous acid (HBrO)? Ka = 2.8 ✕ 10-9
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[H3O+] = sqrt ((2.8 x 10^-9)(0.216)) = 2.5 x 10^-5 M
pH = -log [H3O+] = -log (2.5 x 10^-5) = 4.61
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