Question

What is the pH of the 10⁻⁸ M HCl?

Answer 1

pH WILL BE
pH +poH =14
pH +8=14
pH =14-8=6

Answer 2

Answer:

6.95

Explanation:

pH = - log [$H^{+}$]

[$H^{+}$] = $10^{-8}$

But HCl is strong acid so, its pH cannot be 8 or more than 7.

So, pH = 1 x $10^{-8}$ + 1 x $10^{-7}$

           = 1 x $10^{-8}$ + 10 x $10^{-8}$

           = 1.1 x $10^{-7}$

     pH = 7 - log 1.1

    pH = 6.95

In this case, pH should be slightly less than 7.