Question

What is the POH of a solution with PH6?

Answer 1

The relevant equations are:

1.[H+] [OH-] = 1x10^-14

2.pH + pOH = 14

From these we know that:

3. [H+] = 10^-pH (from 1)

4. pH = 14 - pOH (from 2)

Therefore, substituting 4 into 3, the general equation relating pOH to [H+] is:

[H+] = 10^(-14+pOH)

So, if pH = 6 then:

pOH = 14 - 6 = 8

[H+] = 10^(-14 + 8) = 10^-6