what is the position of 999 in these sequence 100,109,118
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An = A1 + (n-1)d
So, 999 = 100 + (n-1)9
999-100 = 9n -9
899 -9 = 9n
890/9 = n
n= 98.88
Therefore, it will be the 99th term.
(Since it has crossed the number 98)
So, 999 = 100 + (n-1)9
999-100 = 9n -9
899 -9 = 9n
890/9 = n
n= 98.88
Therefore, it will be the 99th term.
(Since it has crossed the number 98)
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