Question

What is the potential of a cell containing two hydrogen electrodes, in which the anode is in contact with 10????5m hcl and the cathode is in contact with 1000 times the concentration of hcl as that of the anode?

Answer 1

As not mentioned, we will work on this while taking number of moles equal to 1
The concentration of HCl at anode must've been $10^{-5}$ because concentration of $10^5$ would be enough to not allow electricity to pass
The concentration of HCl at anode is 1000 time the concentration of HCl at anode which will be $10^{-2}$
To find the Potential,
$E^o_{cell}= \frac{0.0591}{n} log \frac{C_{2}}{C_{1}}$
$E^o_{cell}=0.0591log \frac{10^{-2}}{10^{-5}}$
$E^o_{cell}= 0.0591*3$
$E^o_{cell}=0.1773V$

Answer 2

Answer:

In  this cathode and anode boh aare hydrogen electrode  

[H^+] in cathode = 10 (power ngative 2 ) as the con of HCl is 1000 timess greater than that of anode and [H^+]  at anode is 10 (power negative 5 )

E^0 cell = 0 as cathode and anode are htdrogen , therefore  

EMF of cell = 0.059 / 1   log 10^-2 / 10^ -5 = 0.059 x  3 =0.177V

Explanation: