Question

what is the predecessor of the product of the place value of 2 in 729and the face value of 3 in 135?​

Answer 1

Solution:

i ) Place value of 2 in 729 =

2 × 10 = 20

ii ) Face value of 3 in 135 = 3

iii ) Product of 20 and 3

= 20 × 3

= 60

iv ) Predeccessor of 60

= 60 - 1

= 59

Therefore ,

Required number = 59

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