What is the prlerpendicular distance of the point (4, 3) from X-axis
Answers
Answered by
2
point on x axis that is perpendicular = (4, 0)
so perpendicular distance = √{(x2 - x1)² + (y2 - y1)²}
= √(4-4)² + 3²
= √0² + 9
= √9
= 3 units.
so perpendicular distance = √{(x2 - x1)² + (y2 - y1)²}
= √(4-4)² + 3²
= √0² + 9
= √9
= 3 units.
Similar questions