Question

What is the probability in a leap year picked at random,getting a 53 sundays

Answer 1

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The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays is 2/7.

Answer 2

Answer:

In an year, the number of weeks are 52. There are seven days in a week. Totally there should have been 52*7=364. But there are 366 days in a leap year. Hence the probability of a Sunday is 2/7 as the number of days in a week are the total number of outcomes