what is the probability leap year 52 mondays 53 sundays
Answers
A non-leap year has 365 days
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 52 x 7 = 364 days .
365– 364 = 1day extra.
In a non-leap year there will be 52 Sundays and 1day will be left.
This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.
Of these total 7 outcomes, the favourable outcomes are 1.
Hence the probability of getting 53 sundays = 1 / 7.
2)
∴ probability of getting 52 sundays = 1 - 1/ 7 = 6 / 7.
Answer:
1/7
I HOPE YOU WILL SATISFY THE EXPLANATION
Step-by-step explanation:
A leap year has 366 days. Now 364 is divisible by 7 and therefore there will be two excess week days in a leap year. The two excess week days can be (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday). So, the sample space S has 7 pairs of excess week days. i.e. n(S) = 7.
Now we want the desired event E to have 53 Sundays and 53 Mondays . E consists of only one pair in S which is (Sunday, Monday). So n(E) = 1
Hence, the probability that a leap year will contain 53 Sundays and 53 Mondays = n(E)/n(S) = 1/7