Math, asked by sunitha1983, 8 months ago

what is the probability of getting 53 Sundays in an ordinary year​

Answers

Answered by BrainlyHeart751
4

Answer:

1/7

Step-by-step explanation:

For 52 weeks, There will be 52 Sundays. The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday. Out of these 7 total outcomes, the favorable outcomes are 1. Hence the probability of getting 53 Sundays = 1/7.

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Answered by akashhiremath001
2

Answer:

total number of days n(s)= 365

getting of 53 Sundays n(a)=53

p(a)=n(a)/n(s)

= 53/365.

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