Question

what is the probability of getting a 'nine' or 'ten' on a single throw of two dice?​

Answer 1

Answer:

Total No. of outcomes = 36

Combinations to form sum as 9=(4,5),(5,4),(6,3),(3,6)

P (getting sum as 9)=4/36

=1/9

Hope this helps.

MARK THIS AS BRAINLIST.

Answer 2

The probability of getting nine or ten on a single throw of two dice is $\frac{7}{36}$

Step-by-step explanation:

Given Data

To Find- Probability of getting 9 or 10 on a single throw dice

Total possible outcomes n(s) = 36

possibilities of getting nine n(9) = (3,6) , (6,3), (4,5) and  (5,4)

Possibilities of getting ten n(10) = (5,5) ,(6,4) and (4,6)

Therefore number of possibilities of getting nine = 4

And number of possibilities of getting ten = 3

Probability is equal to the ratio of Number of possibilities to the total number of outcomes.

Probability of getting 9 or ten = $\frac{n(9)}{n(s)} + \frac{n(10)}{n(s)}$

Probability of getting 9 or ten = $\frac{4}{36} + \frac{3}{36}$

Probability of getting 9 or ten = $\frac{4+ 3}{36}$

Probability of getting 9 or ten = $\frac{7}{36}$

Therefore the probability of getting 9 or 10 on a single throw of two dice is $\frac{7}{36}$

To Learn More ...

https://brainly.in/question/2575582