What is the probability of getting an odd sum of the scores in a throw of two dices?
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Answered by
10
1/2 is the answer because 6/12 is the probability
Answered by
25
n(S)=36
let A be the event of getting an odd sum of scores
A= {(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(3,6),(4,1),(4,3),(4,5),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)}
n(A)=18
P(A)=n(A)/n(S)
=18/36
P(A)=1/2
by SK mathematics
let A be the event of getting an odd sum of scores
A= {(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(3,6),(4,1),(4,3),(4,5),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)}
n(A)=18
P(A)=n(A)/n(S)
=18/36
P(A)=1/2
by SK mathematics
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