Math, asked by harshkhulwe07, 4 hours ago

What is the probability of getting at least a head if three coins are tossed simultaneously?​

Answers

Answered by inayausmanjt
1

Answer:

n(E3) = 3. Therefore, P(getting 1 head) = P(E3) = n(E3)/n(S) = 3/8. and, therefore, n(E4) = 7. Therefore, P(getting at least 1 head) = P(E4) = n(E4)/n(S) = 7/8.

Step-by-step explanation:

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