Question

What is the probability of getting atleast one head in throwing two coins​

Answer 1

Answer:

GIVEN :-

• two coins are tossed,
• the sample space of possible outcomes would be the set

• S = {HH, HT, TH, TT}

TO FIND :-

▫️ probability of getting atleast one head

FORMULAE :-

$P(E) = \frac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: outcomes}$

SOLUTION :-

• where H: the outcome is a “Head” and T: the outcome is a “Tail” and the probabilities associated with each of these outcomes are equal assuming the coins are fair.

• When we say at most 1 “Head” outcome, it means that only 1 of the two coins show up a “Head” or that the no “Head” outcome shows up.

• If A is the event obtaining at most 1 “Head” outcome, then the set of outcomes that makes up event A is

➡️A = {(HT), (TH), (TT)}

➡️Hence, the probability of event A is

➡️P(A) = 3/4 = 0.75

Answer 2

Answer:

the probability of getting heads on the toss of coin is 0.5 . If we consider all possible outcomes of the toss of two coins., there is only one outcomes of the four in which both coins have come up heads , so the probability of getting heads on both coins