What is the probability of getting equilateral triangles from the vertices of a regular hexogen ?
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The number of vertices in the regular hexagon = 6 To form a triangle, we need choose 3 vertices out of 6 vertices of a hexagon Number of ways to choose 3 vertices = 6C3 = 20 So, Total number of triangles can be formed by choosing 3 vertices = 20 Number of equilateral triangles can be formed by choosing 3 vertices = 2 Now, ∴ Probability that the triangle with 3 vertices is equilateral triangle = 2/20 =1/10
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Below Follow Rules of Triangle …..
Total possible cases = 6 C 3
Favourable cases =2
So the probability is = 2/6 C 3 =1/10.
Because there can be 2 2 equilateral triangles possible and total number of triangles possible would be (6/3) the answer is 1/10.
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