Question

What is the probability of getting no head when two coins are tossed

simultaneously?​

Answer 1

Answer:

Let E4 = event of getting no head. Then, E4 = {TT} and, therefore, n(E4) = 1. Therefore, P(getting no head) = P(E4) = n(E4)/n(S) = ¼.

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Answer 2

Explanation:

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