what is the probability of having 53 sunday in a non leap year?
Answers
Answered by
1
here is ur answer my friend,
...1/7...
STEPS
the one day left can be a Monday, tuesday, Wednesday,thursday, friday, Saturday and sunday. that means there r 7 total outcome. so probability for 53 Mondays will be 1/7
hope it helps
Pls mark as brainliest..
...1/7...
STEPS
the one day left can be a Monday, tuesday, Wednesday,thursday, friday, Saturday and sunday. that means there r 7 total outcome. so probability for 53 Mondays will be 1/7
hope it helps
Pls mark as brainliest..
deepa214:
but can plzz explain me the steps
Answered by
1
A non-leap year has 365 days
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 52 x 7 = 364 days .
365– 364 = 1day extra.
In a non-leap year there will be 52 Sundays and 1day will be left.
This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.
next
where is the probability how to get that
That 1 day can sometimes bcm Sunday
Total days =7
Did u clear it
yup thank you
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