Question

what is the probability of having 53 Thursdays in a non - leap year?
answer please

Answer 1

It has been wrongly circled as Wednesday.pls Make it as thursday


And the answer is correct

Pls mark it as the brainliest

Answer 2

Answer:

The probability of having 53 Thursdays in a non-leap year is $\frac{6}{7}$

Step-by-step explanation:

In a non-leap year, there are 365 days, i.e. 52 weeks.

52 weeks = 364 days

1 year = 52weeks and 1 day

This extra one day can be mon, tue, wed, thu, fri, sat, or sun.

Total number of outcomes = 7

Number of favorable outcomes =1

Hence the probability of getting 53 Thursday= $\frac{1}{7}$

P(having 53 Thursdays) =$\frac{7-1}{7} \\\frac{6}{7}$