what is the probability of non leap year ending with tuesday
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we know, number of days in non -leap year = 365 days
and number of days in a week = 7 days
so, there are 52 week and 1 day in a non leap year. [ as we see 365 = 7 × 52 + 1 ]
extra day is equally likely : Sunday , Monday , Tuesday , Wednesday, Thursday, Friday, Saturday .
hence, favourable outcomes, n(E) = 1
sample space, n(S) = 7
so, probability = n(E)/n(S) = 1/7 .
hence, probability of non leap year ending with Tuesday is 1/7
and number of days in a week = 7 days
so, there are 52 week and 1 day in a non leap year. [ as we see 365 = 7 × 52 + 1 ]
extra day is equally likely : Sunday , Monday , Tuesday , Wednesday, Thursday, Friday, Saturday .
hence, favourable outcomes, n(E) = 1
sample space, n(S) = 7
so, probability = n(E)/n(S) = 1/7 .
hence, probability of non leap year ending with Tuesday is 1/7
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